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Binary Signals in AWGN

The following signal set is used to transmit equally likely messages over an AWGN channel with spectral height N0/2:

\begin{displaymath}
\begin{array}
{l}
 s_0(t) = \left\{
 \begin{array}
{cl}
 1 &...
 ...eq t < T$}\\  0 & \mbox{else.}
 \end{array} \right. \end{array}\end{displaymath}

The amplitude A is positive, A>0.

1.
Draw a block diagram of the optimum receiver.
2.
Compute the probability of error achieved by your receiver from part (a) as a function of the amplitude A.
3.
Consider now the following receiver:


\begin{picture}
(440,260)(40,530)
 
\setlength {\unitlength}{0.01in}
 %
 \put(14...
 ...0,0)[b]{$\phi_0(t)$}}
 \put(140,540){\makebox(0,0)[b]{$\phi_1(t)$}}\end{picture}

In the diagram above, the two functions $\phi_0(t)$ and $\phi_1(t)$ are chosen as:

\begin{displaymath}
\begin{array}
{l}
 \phi_0(t) = \left\{
 \begin{array}
{cl}
 ...
 ...t < T$}\\  0 & \mbox{else.}
 \end{array} \right. 
 \end{array} \end{displaymath}

Compute the conditional distributions of the two integrator outputs. Notice that you will have to compute four such distributions: fR0|b=0, fR0|b=1, fR1|b=0 and fR1|b=1.

4.
Is it possible to chose coefficients a and b such that the receiver in part (c) achieves the same probability of error as the optimum receiver?

If your answer is yes, compute the values of a and b that minimize the probability of error and explain why optimum performance is achieved.

If your answer is no, compute the probability of error of the receiver in part (c) as a function of the coefficients a and b.


next up previous
Next: Timing Error Up: Collected Problems Previous: Linear, time-invariant systems
Prof. Bernd-Peter Paris
3/3/1998