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AM Modulation

Throughout this problem, assume that the message signal m(t) is given as $m(t)=\cos(2 \pi f_m t)$. The carrier frequency fc is much higher than fm.
1.
Assume m(t) is modulated using conventional DSB AM. Sketch the resulting (time-domain) signal.
2.
Compute and sketch the Fourier transform of the modulated signal.
3.
Repeat parts (a) and (b) if DSB-SC AM is used.
4.
For the remainder of the problem, assume that m(t) is input to the system in Figure 1. The cutoff frequency of the lowpass filters equals fm. Compute x1(t) and x2(t) as well as their Fourier transforms X1(f) and X2(f).
5.
Compute the ouputs of the lowpass filters, y1(t) and y2(t), as well as their Fourier transforms Y1(f) and Y2(f).
6.
Compute the output signal s(t) and its Fourier transform S(f)
7.
How would you describe what this system does?

  
Figure 1: AM modulation
\begin{figure}
\centering
\setlength{\unitlength}{0.0125in} %
\begin{picture}
...
...]{$s(t)$ }}
\put(365,685){\makebox(0,0)[lt]{$-$ }}
\end{picture}
\end{figure}

Hint: The following trigonometric identities may be useful:

\begin{displaymath}\begin{array}{l}
\cos x \cdot \cos y = \frac{1}{2} \cos(x-y)...
... y) = \cos x \cdot \cos y \mp \sin x \cdot \sin y
\end{array} \end{displaymath}



Prof. Bernd-Peter Paris
2002-04-22