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TCOM 500: Modern Telecommunications
Prof. B.-P. Paris
Homework 5
Due: March 4, 2010
For example, if a = 3 and the message is “d,” then the ciphertext is y = 3 ⋅ 4 = 12. If the message is “k,” the ciphertext is y = 3 ⋅ 11 mod 26 = 7.
For a key a to be acceptable, the value of a must be invertible modulo 26. That means the correspondence btween x and y can be uniquey inverted. A case that does not have this property is a = 4, because then both x = 3” (“c”) and x = 16 (“p”) lead to y = 12. One can show that an a is invertible if it has no common factors with 26. Hence, 4 is not invertible because both 4 and 26 can be divided by 2.