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Amplitude Modulation

Consider the following amplitude modulated signal,

\begin{displaymath}
x(t) = (A + m(t)) \cdot \cos(2\pi f_ct).\end{displaymath}

The constant A has been chosen such that (A+m(t))>0 for all t. Furthermore, the spectrum of the message signal m(t) is

\begin{displaymath}
M(f) = \Pi(f/2f_m) = \left\{
\begin{array}
{cl}
1 & \mbox{for $\vert f\vert < f_m$} \\ 0 & \mbox{otherwise.}\end{array}\right.\end{displaymath}

The carrier frequency fc is much larger than fm.
1.
Sketch the spectrum of x(t).
2.
To demodulate x(t) we use the following system.

\begin{picture}
(90,30)

\setlength {\unitlength}{1.5mm}
 
\put(0,10){\makebox(9...
 ...put(70,15){\vector(1,0){10}}
\put(81,10){\makebox(9,10)[l]{$y(t)$}}\end{picture}
The subsystems labeled $(\cdot)^2$ and $\sqrt{\cdot}$ take the square and square-root of their respective inputs. Sketch the spectrum of the signal x(t)2.
3.
Assume the transfer function of the lowpass is $H(f)=\Pi(f/4f_m)$.Find an expression for the signal xL(t).
4.
Give an expression for the output signal y(t).
Hint: You may need: $\cos^2(x) = \frac{1}{2}(1+\cos(2x))$.



Prof. Bernd-Peter Paris
3/2/1998