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Frequency-Shift Keying (FSK)

In a coherent FSK signalling scheme the signals $s_1(t)$ and $s_2(t)$ are defined to be

\begin{displaymath}
\begin{array}{ccl}
s_1(t) & = & A \cos(2 \pi ( f_c + \frac{\...
... & = & A \cos(2 \pi ( f_c - \frac{\Delta\!f}{2})t)
\end{array}\end{displaymath}

These signals are used to transmit equally-likely bits over a channel which adds white Gaussian noise of spectral height $\frac{N_0}{2}$ to the signal.
  1. Assuming $f_c \gg \Delta\!f$, show that the ``correlation coefficient'' $\rho$ of the signals $s_1(t)$ and $s_2(t)$, defined as

    \begin{displaymath}
\rho = \frac{(s_1(t),s_2(t))}{\vert\vert s_1(t)\vert\vert \cdot \vert\vert s_2(t)\vert\vert}
\end{displaymath}

    is given approximately by

    \begin{displaymath}
\rho = \frac{\sin(2\pi\Delta\!fT)}{2\pi\Delta\!fT} =
\mbox{sinc}(2\pi\Delta\!fT),
\end{displaymath}

    where $T$ is the duration of a bit interval.
  2. What is the minimum value of the frequency shift $\Delta\!f$ for which the signals are orthogonal?
  3. Draw a block diagram of the receiver which attains the minimum probability of error.
  4. Compute the minimum probability of error as a function of $\rho$.
  5. What is the value of $\Delta\!f$ that minimizes the probability of error?

Hint: You may need these equations:

\begin{displaymath}
\cos(x+y) \cdot \cos(x-y) = \cos^2(x) - \sin^2(y)
\end{displaymath}


\begin{displaymath}
\int \cos^2(ax)\,dx = \frac{x}{2} + \frac{\sin(2ax)}{4a}
\end{displaymath}


\begin{displaymath}
\int \sin^2(ax)\,dx = \frac{x}{2} - \frac{\sin(2ax)}{4a}
\end{displaymath}


next up previous
Next: Binary Signal Sets Up: Collected Problems Previous: Collected Problems
Dr. Bernd-Peter Paris
2003-01-28