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Frequency-Shift Keying (FSK)

In a coherent FSK signalling scheme the signals s1(t) and s2(t) are defined to be

\begin{displaymath}
\begin{array}
{ccl}
 s_1(t) & = & A \cos(2 \pi ( f_c + \frac...
 ... = & A \cos(2 \pi ( f_c - \frac{\Delta\!f}{2})t) 
 \end{array} \end{displaymath}

These signals are used to transmit equally-likely bits over a channel which adds white Gaussian noise of spectral height $\frac{N_0}{2}$ to the signal.
1.
Assuming $f_c \gg \Delta\!f$, show that the ``correlation coefficient'' $\rho$ of the signals s1(t) and s2(t), defined as

\begin{displaymath}
\rho = \frac{(s_1(t),s_2(t))}{\vert\vert s_1(t)\vert\vert \cdot \vert\vert s_2(t)\vert\vert}
 \end{displaymath}

is given approximately by

\begin{displaymath}
\rho = \frac{\sin(2\pi\Delta\!fT)}{2\pi\Delta\!fT} =
 \mbox{sinc}(2\pi\Delta\!fT),
 \end{displaymath}

where T is the duration of a bit interval.
2.
What is the minimum value of the frequency shift $\Delta\!f$ for which the signals are orthogonal?
3.
Draw a block diagram of the receiver which attains the minimum probability of error.
4.
Compute the minimum probability of error as a function of $\rho$.
5.
What is the value of $\Delta\!f$ that minimizes the probability of error?

Hint: You may need these equations:

\begin{displaymath}
\cos(x+y) \cdot \cos(x-y) = \cos^2(x) - \sin^2(y)
 \end{displaymath}

\begin{displaymath}
\int \cos^2(ax)\,dx = \frac{x}{2} + \frac{\sin(2ax)}{4a}
 \end{displaymath}

\begin{displaymath}
\int \sin^2(ax)\,dx = \frac{x}{2} - \frac{\sin(2ax)}{4a}
 \end{displaymath}



Prof. Bernd-Peter Paris
3/3/1998