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Instantaneous Frequency

Consider the chirp signal

\begin{displaymath}x(t)=\cos(2\pi(at^2+bt)).
\end{displaymath}

1.
Determine values for a and b, such that the instantaneous frequency of x(t) will start at 0 Hz and end at 12000 Hz over the time interval $0\leq t \leq 10$ seconds.
2.
Plot the instaneous frequency versus time over the interval $0\leq t \leq 10$ seconds.
3.
Now assume that this chirp signal is sampled at rate fs=8000 Hz. Plot the instaneous normalized (digital) frequency of the sampled signal versus time over the interval $0\leq t \leq 10$ seconds.



Prof. Bernd-Peter Paris
2001-10-02